n2 g; 3h2; →2nh3; عدد مولات g 40 من عنصر النيون ( الكتلة الذرية Ne= 20 ) تساوي Considerthe reaction 2NH3(g) → N2(g) + 3H2(g)If the rate Δ[H2]/Δt is 0.030 mol L-1 s-1, then Δ[NH3]/Δt is 化学反应N23H2 2NH3的能量变化如图所示，该反应的热化学方程式是( ) A.N2(g)+3H2(g) 2NH3(l) H=2(a-b-c)kJ/mol B.N2(g)+3H2(g) 2NH3(g) H=2(b-a)kJ/mol C.N2(g)+H2(g) NH3(l) H=(b+c-a)kJ/mol D.N2(g)+H2(g) NH3(g) H=(a+b)kJ/mol Forthe reaction N2(g) + 3H2(g) + 2NH3(g), if the rate of disappearance of hydrogen is 3.0 x 10 -3 mole/L/sec. For the reaction N2(g) + 3H2(g) + 2NH3(g), if the rate of disappearance of hydrogen is 3.0 x 10 -3 mole/L/sec. Then the rate of reaction will be (A) 3.0 x 10 -3 mole/L/sec (B) 1.0 x 10-3 mole/L/sec (C) 2.0 x 10-3 mole/L/sec (D) 1.5 N2(g) +3H2(g) — 2NH3(g) Yukarıdaki tepkimeye göre 7g N2 gazı, yeterli miktarda H2 gazı ile tepkimeye girdiğinde oluşan MH3 gazının 0 °C’ta ve 5,6 L’l Kitap Cevapları TIKLA Test Çöz TIKLA N2g) + 3H2(g) 2NH3(g) Determina el reactivo limitante en cada una de las siguientes mezclas: a) 3.0 moles de N2 y 5.0 moles de H2 b) 8.0 moles de N2 y 4.0 moles de H2 2 Ver respuestas Publicidad Publicidad XannXnails XannXnails a) 3mol H2 ----- 1mol N2. 5mol H2 ----x= 1,66mol N2. Fora reaction, N2(g) + 3H2(g) + 2NH3(g) identify dihydrogen (H2) as a limiting reagent in the following reaction mixtures. (2019 Main, 9 April 1) (a) 56 g of N2 + 10 g of H, (b) 35 g of N2 + 8g of H, (c) 14 g of N2 + 4 g of H2 (d) 28 g of N2 +6g of H, < PreviousNext > Answer. Thereaction N2 (g) + 3H2 (g)→ 2NH3 (g) has values ΔHo = -92.38 kJ and ΔSo = -198.3 J/K. For this reaction at 100.0 oC ΔGo = kJ For this reaction at 500.0 oC ΔGo = kJ Speaking qualitatively and considering only the signs for ΔHo and ΔSo, we can say that this reaction is. r8Mm5. You first need to solve for the moles of N2. This is done by dividing the mass given by the molar mass of N2. The molar mass is calculated by adding the molar mass of all the atoms N * 2 = N2Using as the molar mass of N2 perform the following / = N2Because the equation in balanced we already know that there are two moles of ammonia produced for every one mole of N2. This means we just need to multiply the number of moles of N2 by 2 in order to get the number of moles of ammonia N2 * 2mol NH3/1mol N2 = NH3After solving for the moles of ammonia, we need to convert the moles to grams. This is done using the molar mass of ammonia which is solved as N2 + 3 H = NH3The moles of ammonia we found earlier is then multiplied by the molar mass of ammonia to convert it to NH3 * NH3 = NH3Therefore, your answer should be of ammonia are produced. >>Class 11>>Chemistry>>Equilibrium>>Applications of Equilibrium Constants>>N2 g + 3H2 g 2NH3 g for the reacOpen in AppUpdated on 2022-09-05SolutionVerified by TopprGiven that initially, the mole ratio was of . Since, of the metal has reacted,Total no. of moles reacted No. of moles of at equillibrium Equillibrium pressure Partial pressure of at equillibrium Solve any question of Equilibrium with-Was this answer helpful? 00Similar questionsMore From ChapterLearn with Videos Practice more questions